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How to Swap Two Numbers Without Using Temporary Variable or Arithmetic Operators?

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You have done swapping of two numbers using temporary variable or by using arithmetic operators. It can be done in following way. Lets take two numbers a=5 and b=7. Using Temporary Variable temp=a;            //temp becomes 5 a=b;                 //a becomes 7 b=temp;            //b becomes 5 Also Read: C++ program to swap two numbers using pointers Also Read: C++ …

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Java program to swap two numbers

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class Swap { public static void main(String…s) { int a,b,temp; a=Integer.parseInt(s[0]); b=Integer.parseInt(s[1]); System.out.println(“nBefore Swap:n”+”a=”+a+”tb=”+b); temp=a; a=b; b=temp; System.out.println(“nAfter Swap:n”+”a=”+a+”tb=”+b); } }

C++ program to find cube of a number using macros

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Also Read: C++ program to swap two numbers using macros Also Read: C++ Program to find cube of a number using function #include<iostream.h> #include<conio.h> #define CUBE(x) (x*x*x) void main() { clrscr(); int n,cube; cout<<“Enter a number:”; cin>>n; cube=CUBE(n); cout<<“Cube=”<<cube; getch(); }

C program to print size of different data types

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#include<stdio.h> #include<conio.h> void main() { clrscr(); printf(“TypettttSize (bytes)”); printf(“nCharacterttt    %d”,sizeof(char)); printf(“nIntegertttt    %d”,sizeof(int)); printf(“nLong intttt    %d”,sizeof(long int)); printf(“nFloattttt    %d”,sizeof(float)); printf(“nDoubletttt    %d”,sizeof(double)); printf(“nLong doublettt    %d”,sizeof(long double)); getch(); }

C++ program to swap two numbers using macros

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#include<iostream.h> #include<conio.h> #define SWAP(a,b) {int temp; temp=a; a=b; b=temp;} void main() { clrscr(); int x,y; cout<<“Enter two numbers:”; cin>>x>>y; cout<<“x=”<<x<<” y=”<<y; SWAP(x,y); cout<<“nx=”<<x<<” y=”<<y; getch(); }