Here is the program for transpose of matrix in C.
We first read a matrix of size mxn and then find its transpose by just interchanging the rows and columns i.e. rows become columns and columns become rows.
Transpose of Matrix in C
#include<stdio.h>
int main()
{
int a[5][5],i,j,m,n;
printf("How many rows?");
scanf("%d",&n);
printf("How many columns?");
scanf("%d",&m);
printf("\nEnter the matrix:\n");
for(i=0;i<m;++i)
for(j=0;j<n;++j)
scanf("%d",&a[i][j]);
printf("\nTranspose of given matrix:\n");
for(i=0;i<m;++i)
{
for(j=0;j<n;++j)
printf("%d ",a[j][i]);
printf("\n");
}
return 0;
}
Output
How many rows?3
How many columns?3
Enter the matrix:
1 2 3
4 5 6
7 8 9
Transpose of given matrix:
1 4 7
2 5 8
3 6 9
