Here you will get simple C++ program to find roots of quadratic equation ax2+bx+c=0.
#include<iostream> #include<math.h> //to calculate square root using namespace std; int main() { float root1,root2,a,b,c,d,imaginaryPart,realPart; cout<<"Quadratic Equation is ax^2+bx+c=0"; cout<<"\nEnter values of a,b and c:"; cin>>a>>b>>c; d=(b*b)-(4*a*c); if(d>0) { cout<<"\nTwo real and distinct roots"; root1=(-b+sqrt(d))/(2*a); root2=(-b-sqrt(d))/(2*a); cout<<"\nRoots are "<<root1<<" and "<<root2; } else if(d==0) { cout<<"\nTwo real and equal roots"; root1=root2=-b/(2*a); cout<<"\nRoots are "<<root1<<" and "<<root2; } else{ cout<<"\nRoots are complex and imaginary"; realPart = -b/(2*a); imaginaryPart = sqrt(-d)/(2*a); cout<<"\nRoots are "<<realPart<<"+"<<imaginaryPart<<"i and "<<realPart<<"-"<<imaginaryPart<<"i"; } return 0; }
Output
Quadratic Equation is ax^2+bx+c=0
Enter values of a,b and c:3
4
1
Two real and distinct roots
Roots are -0.333333 and -1
how to write the program of complex root?
nice !
HOW TO WRITE A PROGRAM FOR MEMORY GAME ; PLEASE HELP TO DO IT EASILY !!!!!!!!!!!
The first two conditions, where d>0 or d=0 are same. In the third condition, that is d<0, do the following:
cout<<"Roots are complex and distinct";
int i;
root1= (-b +sqrt(-d)i)/(2*a);
root2= (-b – sqrt(-d)i)/(2*a);
cout<<"Roots are "<<root1<<" and "<<root2<<endl;
How do I make a switch statement for the program to solve any quadratic equation.